## May 2003

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In my May diary I posed the following brain-teaser:

Brothers Angus and Mac raise sheep in the Highlands. They take the flock to market one day, and sell all the sheep. By odd coincidence, the price per sheep was the same as the number of sheep, that is, the total sum — number of British pounds sterling — received by the brothers was a perfect square.

The brothers collect their earnings as a stack of £10 notes and a few £1 coins. They go home and divide it, fifty-fifty. The ten-spots are counted out, but Mac winds up with one more ten-spot than Angus. Mac shoves the stack of coins across the table to Angus and then says: "That makes it close to even, but not quite. I'll write you a draft to square our accounts."

How much was the draft for?

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*Solution*

The solution hinges on the following fact about perfect squares. (That is, the squares of whole numbers.)

• A perfect square that has an odd number of tens must end in 6.

This is because if you square a whole number your answer is (a) an even number of tens, plus (b) the square of your number's units. Examples:

Square 12. You get 140 (that is, fourteen tens) plus 4 (the square of 2).

Square 37. You get 1320 (that is, 132 tens) plus 49 (the square of 7).

Square 7,239. You get 52,403,040 (that is, 5,240,304 tens) plus 81 (the square of 9).

Square 24. You get 570 (that is, 57 tens) plus 6.

The algebra is straightforward. If the number of tens in your original number is
*T*, and the number of units is
*U*, then your number is 10*T* + *U*. Squaring that gives you
100×*T*^{ 2} + 20×*T*×*U* + *U*^{ 2}.
The
number of tens in this answer is
100×*T*^{ 2} + 20×*T*×*U*, which is certainly an even
number: it is
2 times the whole number 50×*T*^{ 2} + 10×*T*×*U*.

The only way a perfect square can have an odd number of tens, therefore, is by acquiring them when you add
*U*^{ 2}. If I add
something to an
even number and get an odd result, the thing I added must have been odd. The number of tens in
*U*^{ 2} therefore needs to be
odd. Since
*U* is a single digit from 0 to 9, *U*^{ 2} is one of the following: 0, 1, 4, 9, 16, 25,
36, 49, 64, 81. The only ones
with an odd number of tens are 16 and 36. Q.E.D.

Now, since the total sum the brothers are dividing is a perfect square, and since we know that the number of tens is
odd, we know that the number of
units is 6. In bills, Hughie has one more 10-spot than Angus. After giving him the 6 coins, he is up by only 4
pounds.

Therefore the draft is for two pounds.